I want to reproduce a 'typical application' AC-coupled-inverting-amplifier circuit as shown in the LM358 datasheets.

This one is from ST's datasheet:

This one is from Diodes Incorporated's datasheet (with an error, isn't Rf supposed to be 100K for a gain of 10?):

Let's reproduce the circuit in Fritzing for a structured breadboard layout.

But first, what values should the capacitors be? I suppose they should work like a high-pass filter, allowing the AC of the desired frequency to pass while blocking DC. So what value would a capacitor be in a high-passfilter for say 40 Hz? When I test with Falstad simulator a 1uF seems to be enough.

let's say that if you have an infinite load impedance, well... no need to worry about the capacitor value: even a 1pF will work fine without deteriorating your AC signal. However, the presence of a load (was it desired or not) makes things a little bit trickier (source)

Some things I learned from TI's 'A Single-Supply Op-Amp Circuit Collection' PDF:

• R2 and R3 are equal values, selected with power consumption vs allowable noise in mind.
• Capacitor C1 forms a low-pass filter to eliminate conducted noise on the voltage rail.
• (about Cin and Co) ac-couple the signals to and from the op-amp stage. In this way, the input and output devices can be referenced to ground, and the op-amp circuitry can be referenced to a virtual ground.

With V+ = 5V and Vin = 100 mV @ 40Hz this is the result. Pretty close to a good -10 amplification!

Question: what is the purpose of the 6.2k resistor Cb? And C1 for that matter? When I remove them neither seem to have any effect on the output.